Base | Representation |
---|---|
bin | 10100011000000101010… |
… | …000111000100010001011 |
3 | 11221212021122222202000111 |
4 | 110120011100320202023 |
5 | 140420201344303233 |
6 | 2551133114415151 |
7 | 203110304435005 |
oct | 24300520704213 |
9 | 4855248882014 |
10 | 1400247650443 |
11 | 49a929326784 |
12 | 1a74641314b7 |
13 | a2073005cb5 |
14 | 4bab5473375 |
15 | 26654c7cacd |
hex | 1460543888b |
1400247650443 has 2 divisors, whose sum is σ = 1400247650444. Its totient is φ = 1400247650442.
The previous prime is 1400247650407. The next prime is 1400247650509. The reversal of 1400247650443 is 3440567420041.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1400247650443 - 229 = 1399710779531 is a prime.
It is a super-2 number, since 2×14002476504432 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1400247650396 and 1400247650405.
It is not a weakly prime, because it can be changed into another prime (1400247350443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700123825221 + 700123825222.
It is an arithmetic number, because the mean of its divisors is an integer number (700123825222).
Almost surely, 21400247650443 is an apocalyptic number.
1400247650443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400247650443 is an equidigital number, since it uses as much as digits as its factorization.
1400247650443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 322560, while the sum is 40.
The spelling of 1400247650443 in words is "one trillion, four hundred billion, two hundred forty-seven million, six hundred fifty thousand, four hundred forty-three".
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