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140031421110157 is a prime number
BaseRepresentation
bin11111110101101110011011…
…000111001101011110001101
3200100210212120111121022121211
4133311232123013031132031
5121323233322301011112
61213453314034254421
741331636104232163
oct3765563307153615
9610725514538554
10140031421110157
1140688aa0672385
121385703b727411
136019ba2335a85
1426817b2381233
15112c812c7a0a7
hex7f5b9b1cd78d

140031421110157 has 2 divisors, whose sum is σ = 140031421110158. Its totient is φ = 140031421110156.

The previous prime is 140031421110127. The next prime is 140031421110197. The reversal of 140031421110157 is 751011124130041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88254488316996 + 51776932793161 = 9394386^2 + 7195619^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140031421110157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140031421110127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70015710555078 + 70015710555079.

It is an arithmetic number, because the mean of its divisors is an integer number (70015710555079).

Almost surely, 2140031421110157 is an apocalyptic number.

It is an amenable number.

140031421110157 is a deficient number, since it is larger than the sum of its proper divisors (1).

140031421110157 is an equidigital number, since it uses as much as digits as its factorization.

140031421110157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3360, while the sum is 31.

Adding to 140031421110157 its reverse (751011124130041), we get a palindrome (891042545240198).

The spelling of 140031421110157 in words is "one hundred forty trillion, thirty-one billion, four hundred twenty-one million, one hundred ten thousand, one hundred fifty-seven".