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140032413019937 is a prime number
BaseRepresentation
bin11111110101101111010110…
…001111000010111100100001
3200100210222010122001120001002
4133311233112033002330201
5121323242340213114222
61213454000310321345
741332002510306344
oct3765572617027441
9610728118046032
10140032413019937
114068945a56a929
1213857277959255
136019ccc99c739
142681867dc445b
15112c86edae392
hex7f5bd63c2f21

140032413019937 has 2 divisors, whose sum is σ = 140032413019938. Its totient is φ = 140032413019936.

The previous prime is 140032413019921. The next prime is 140032413020021. The reversal of 140032413019937 is 739910314230041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93492674443921 + 46539738576016 = 9669161^2 + 6822004^2 .

It is a cyclic number.

It is not a de Polignac number, because 140032413019937 - 24 = 140032413019921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140032413019891 and 140032413019900.

It is not a weakly prime, because it can be changed into another prime (140032413019537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70016206509968 + 70016206509969.

It is an arithmetic number, because the mean of its divisors is an integer number (70016206509969).

Almost surely, 2140032413019937 is an apocalyptic number.

It is an amenable number.

140032413019937 is a deficient number, since it is larger than the sum of its proper divisors (1).

140032413019937 is an equidigital number, since it uses as much as digits as its factorization.

140032413019937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 489888, while the sum is 47.

Adding to 140032413019937 its reverse (739910314230041), we get a palindrome (879942727249978).

The spelling of 140032413019937 in words is "one hundred forty trillion, thirty-two billion, four hundred thirteen million, nineteen thousand, nine hundred thirty-seven".