Base | Representation |
---|---|
bin | 11111110101110000001101… |
… | …101000011001001000110000 |
3 | 200100211001112101212112022212 |
4 | 133311300031220121020300 |
5 | 121323301241124130222 |
6 | 1213454232430351252 |
7 | 41332034524100240 |
oct | 3765601550311060 |
9 | 610731471775285 |
10 | 140033342411312 |
11 | 40689897147379 |
12 | 1385749705b528 |
13 | 601a11a3b706c |
14 | 26819155d1b20 |
15 | 112c8c67946e2 |
hex | 7f5c0da19230 |
140033342411312 has 80 divisors (see below), whose sum is σ = 316299271622400. Its totient is φ = 58818459135744.
The previous prime is 140033342411311. The next prime is 140033342411321. The reversal of 140033342411312 is 213114243330041.
It is a super-2 number, since 2×1400333424113122 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (140033342411311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 45885062 + ... + 48841637.
It is an arithmetic number, because the mean of its divisors is an integer number (3953740895280).
Almost surely, 2140033342411312 is an apocalyptic number.
It is an amenable number.
140033342411312 is an abundant number, since it is smaller than the sum of its proper divisors (176265929211088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140033342411312 is a wasteful number, since it uses less digits than its factorization.
140033342411312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94726978 (or 94726972 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 140033342411312 its reverse (213114243330041), we get a palindrome (353147585741353).
The spelling of 140033342411312 in words is "one hundred forty trillion, thirty-three billion, three hundred forty-two million, four hundred eleven thousand, three hundred twelve".
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