1400401030013 has 2 divisors, whose sum is σ = 1400401030014. Its totient is φ = 1400401030012.

The previous prime is 1400401030001. The next prime is 1400401030103. The reversal of 1400401030013 is 3100301040041.

Together with next prime (1400401030103) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1290046183204 + 110354846809 = 1135802^2 + 332197^2 .

It is a cyclic number.

It is not a de Polignac number, because 1400401030013 - 2²⁰ = 1400399981437 is a prime.

It is a super-2 number, since 2×1400401030013² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1400401029973 and 1400401030000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1400401030313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700200515006 + 700200515007.

It is an arithmetic number, because the mean of its divisors is an integer number (700200515007).

Almost surely, 2^{1400401030013} is an apocalyptic number.

It is an amenable number.

1400401030013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400401030013 is an equidigital number, since it uses as much as digits as its factorization.

1400401030013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1400401030013 its reverse (3100301040041), we get a palindrome (4500702070054).

The spelling of 1400401030013 in words is "one trillion, four hundred billion, four hundred one million, thirty thousand, thirteen".