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1400402243353 is a prime number
BaseRepresentation
bin10100011000001110011…
…110100110111100011001
311221212200102212212121211
4110120032132212330121
5140421010433241403
62551200320103121
7203114162444131
oct24301636467431
94855612785554
101400402243353
1149a9a8615713
121a74a7a64aa1
13a20990525a9
144bacbbd5ac1
152666361806d
hex1460e7a6f19

1400402243353 has 2 divisors, whose sum is σ = 1400402243354. Its totient is φ = 1400402243352.

The previous prime is 1400402243347. The next prime is 1400402243369. The reversal of 1400402243353 is 3533422040041.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1144703128464 + 255699114889 = 1069908^2 + 505667^2 .

It is an emirp because it is prime and its reverse (3533422040041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1400402243353 - 225 = 1400368688921 is a prime.

It is a super-2 number, since 2×14004022433532 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1400402243753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700201121676 + 700201121677.

It is an arithmetic number, because the mean of its divisors is an integer number (700201121677).

Almost surely, 21400402243353 is an apocalyptic number.

It is an amenable number.

1400402243353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400402243353 is an equidigital number, since it uses as much as digits as its factorization.

1400402243353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 1400402243353 its reverse (3533422040041), we get a palindrome (4933824283394).

The spelling of 1400402243353 in words is "one trillion, four hundred billion, four hundred two million, two hundred forty-three thousand, three hundred fifty-three".