14004123413219 has 2 divisors, whose sum is σ = 14004123413220. Its totient is φ = 14004123413218.

The previous prime is 14004123413129. The next prime is 14004123413221. The reversal of 14004123413219 is 91231432140041.

Together with previous prime (14004123413129) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14004123413219 is a prime.

It is a super-2 number, since 2×14004123413219² (a number of 27 digits) contains 22 as substring.

Together with 14004123413221, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14004123413419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002061706609 + 7002061706610.

It is an arithmetic number, because the mean of its divisors is an integer number (7002061706610).

Almost surely, 2^{14004123413219} is an apocalyptic number.

14004123413219 is a deficient number, since it is larger than the sum of its proper divisors (1).

14004123413219 is an equidigital number, since it uses as much as digits as its factorization.

14004123413219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 35.

The spelling of 14004123413219 in words is "fourteen trillion, four billion, one hundred twenty-three million, four hundred thirteen thousand, two hundred nineteen".