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14004232513 is a prime number
BaseRepresentation
bin11010000101011011…
…11010000101000001
31100010222102201111021
431002231322011001
5212140040420023
610233343145441
71004016004135
oct150255720501
940128381437
1014004232513
115a3702a187
122869ba5281
13142246151b
1496bc993c5
1556e6bc35d
hex342b7a141

14004232513 has 2 divisors, whose sum is σ = 14004232514. Its totient is φ = 14004232512.

The previous prime is 14004232483. The next prime is 14004232537. The reversal of 14004232513 is 31523240041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9638723329 + 4365509184 = 98177^2 + 66072^2 .

It is a cyclic number.

It is not a de Polignac number, because 14004232513 - 213 = 14004224321 is a prime.

It is a super-2 number, since 2×140042325132 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14004232553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002116256 + 7002116257.

It is an arithmetic number, because the mean of its divisors is an integer number (7002116257).

Almost surely, 214004232513 is an apocalyptic number.

It is an amenable number.

14004232513 is a deficient number, since it is larger than the sum of its proper divisors (1).

14004232513 is an equidigital number, since it uses as much as digits as its factorization.

14004232513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 14004232513 its reverse (31523240041), we get a palindrome (45527472554).

The spelling of 14004232513 in words is "fourteen billion, four million, two hundred thirty-two thousand, five hundred thirteen".