Base | Representation |
---|---|
bin | 11111110101111001011111… |
… | …001110001010100001100100 |
3 | 200100212000020110002111221011 |
4 | 133311321133032022201210 |
5 | 121323432140101431040 |
6 | 1213503000542032004 |
7 | 41332536361316416 |
oct | 3765713716124144 |
9 | 610760213074834 |
10 | 140043301202020 |
11 | 40693037675217 |
12 | 138593b6278604 |
13 | 601b0466a6428 |
14 | 26821bc0a89b6 |
15 | 112ccaac123ea |
hex | 7f5e5f38a864 |
140043301202020 has 24 divisors (see below), whose sum is σ = 301263882099768. Its totient is φ = 54651044371200.
The previous prime is 140043301201981. The next prime is 140043301202029. The reversal of 140043301202020 is 20202103340041.
It can be written as a sum of positive squares in 4 ways, for example, as 2122516816996 + 137920784385024 = 1456886^2 + 11743968^2 .
It is a super-2 number, since 2×1400433012020202 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 140043301201982 and 140043301202000.
It is not an unprimeable number, because it can be changed into a prime (140043301202029) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85392256011 + ... + 85392257650.
It is an arithmetic number, because the mean of its divisors is an integer number (12552661754157).
Almost surely, 2140043301202020 is an apocalyptic number.
140043301202020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
140043301202020 is an abundant number, since it is smaller than the sum of its proper divisors (161220580897748).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140043301202020 is a wasteful number, since it uses less digits than its factorization.
140043301202020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 170784513711 (or 170784513709 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 140043301202020 its reverse (20202103340041), we get a palindrome (160245404542061).
The spelling of 140043301202020 in words is "one hundred forty trillion, forty-three billion, three hundred one million, two hundred two thousand, twenty".
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