14004331332161 has 2 divisors, whose sum is σ = 14004331332162. Its totient is φ = 14004331332160.

The previous prime is 14004331332139. The next prime is 14004331332209. The reversal of 14004331332161 is 16123313340041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11696229000625 + 2308102331536 = 3419975^2 + 1519244^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14004331332161 is a prime.

It is a super-2 number, since 2×14004331332161² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14004331332661) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002165666080 + 7002165666081.

It is an arithmetic number, because the mean of its divisors is an integer number (7002165666081).

Almost surely, 2^{14004331332161} is an apocalyptic number.

It is an amenable number.

14004331332161 is a deficient number, since it is larger than the sum of its proper divisors (1).

14004331332161 is an equidigital number, since it uses as much as digits as its factorization.

14004331332161 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 32.

The spelling of 14004331332161 in words is "fourteen trillion, four billion, three hundred thirty-one million, three hundred thirty-two thousand, one hundred sixty-one".