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140043551 is a prime number
BaseRepresentation
bin10000101100011…
…10010100011111
3100202111221122012
420112032110133
5241322343201
621521341435
73320231144
oct1026162437
9322457565
10140043551
117206187a
123aa9787b
132302410b
14148563cb
15c4645bb
hex858e51f

140043551 has 2 divisors, whose sum is σ = 140043552. Its totient is φ = 140043550.

The previous prime is 140043539. The next prime is 140043571. The reversal of 140043551 is 155340041.

140043551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (155340041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140043551 is a prime.

It is a super-2 number, since 2×1400435512 = 39224392353379202, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140043571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70021775 + 70021776.

It is an arithmetic number, because the mean of its divisors is an integer number (70021776).

Almost surely, 2140043551 is an apocalyptic number.

140043551 is a deficient number, since it is larger than the sum of its proper divisors (1).

140043551 is an equidigital number, since it uses as much as digits as its factorization.

140043551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 140043551 is about 11833.9997887443. Note that the first 3 decimals coincide. The cubic root of 140043551 is about 519.3032470579.

Adding to 140043551 its reverse (155340041), we get a palindrome (295383592).

The spelling of 140043551 in words is "one hundred forty million, forty-three thousand, five hundred fifty-one".