Base | Representation |
---|---|
bin | 10100011000010000101… |
… | …111111001111110111111 |
3 | 11221212210002112222201201 |
4 | 110120100233321332333 |
5 | 140421100211112343 |
6 | 2551204200320331 |
7 | 203115134262322 |
oct | 24302057717677 |
9 | 4855702488651 |
10 | 1400440332223 |
11 | 49aa18070419 |
12 | 1a74b87730a7 |
13 | a20a3bca29a |
14 | 4bad2cac7b9 |
15 | 26666b3d94d |
hex | 14610bf9fbf |
1400440332223 has 2 divisors, whose sum is σ = 1400440332224. Its totient is φ = 1400440332222.
The previous prime is 1400440332199. The next prime is 1400440332229. The reversal of 1400440332223 is 3222330440041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1400440332223 - 29 = 1400440331711 is a prime.
It is a super-2 number, since 2×14004403322232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1400440332191 and 1400440332200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400440332229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700220166111 + 700220166112.
It is an arithmetic number, because the mean of its divisors is an integer number (700220166112).
Almost surely, 21400440332223 is an apocalyptic number.
1400440332223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400440332223 is an equidigital number, since it uses as much as digits as its factorization.
1400440332223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 1400440332223 its reverse (3222330440041), we get a palindrome (4622770772264).
The spelling of 1400440332223 in words is "one trillion, four hundred billion, four hundred forty million, three hundred thirty-two thousand, two hundred twenty-three".
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