14004412021 has 2 divisors, whose sum is σ = 14004412022. Its totient is φ = 14004412020.

The previous prime is 14004412013. The next prime is 14004412027. The reversal of 14004412021 is 12021440041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13366596996 + 637815025 = 115614^2 + 25255^2 .

It is a cyclic number.

It is not a de Polignac number, because 14004412021 - 2³ = 14004412013 is a prime.

It is a super-2 number, since 2×14004412021² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14004412021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14004412027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002206010 + 7002206011.

It is an arithmetic number, because the mean of its divisors is an integer number (7002206011).

Almost surely, 2^14004412021 is an apocalyptic number.

It is an amenable number.

14004412021 is a deficient number, since it is larger than the sum of its proper divisors (1).

14004412021 is an equidigital number, since it uses as much as digits as its factorization.

14004412021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 256, while the sum is 19.

Adding to 14004412021 its reverse (12021440041), we get a palindrome (26025852062).

The spelling of 14004412021 in words is "fourteen billion, four million, four hundred twelve thousand, twenty-one".