Base | Representation |
---|---|
bin | 11111110101111010011010… |
… | …111100111010100101110011 |
3 | 200100212002211021202001010112 |
4 | 133311322122330322211303 |
5 | 121323441213122011032 |
6 | 1213503244220451535 |
7 | 41332603250162513 |
oct | 3765723274724563 |
9 | 610762737661115 |
10 | 140044303313267 |
11 | 40693501300231 |
12 | 138596359a9bab |
13 | 601b1761a2572 |
14 | 2682275205843 |
15 | 112cd18bae1b2 |
hex | 7f5e9af3a973 |
140044303313267 has 2 divisors, whose sum is σ = 140044303313268. Its totient is φ = 140044303313266.
The previous prime is 140044303313191. The next prime is 140044303313269. The reversal of 140044303313267 is 762313303440041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140044303313267 is a prime.
It is a super-2 number, since 2×1400443033132672 (a number of 29 digits) contains 22 as substring.
Together with 140044303313269, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (140044303313269) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70022151656633 + 70022151656634.
It is an arithmetic number, because the mean of its divisors is an integer number (70022151656634).
Almost surely, 2140044303313267 is an apocalyptic number.
140044303313267 is a deficient number, since it is larger than the sum of its proper divisors (1).
140044303313267 is an equidigital number, since it uses as much as digits as its factorization.
140044303313267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 435456, while the sum is 41.
The spelling of 140044303313267 in words is "one hundred forty trillion, forty-four billion, three hundred three million, three hundred thirteen thousand, two hundred sixty-seven".
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