140045105041 has 2 divisors, whose sum is σ = 140045105042. Its totient is φ = 140045105040.

The previous prime is 140045105017. The next prime is 140045105063. The reversal of 140045105041 is 140501540041.

140045105041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132116983441 + 7928121600 = 363479^2 + 89040^2 .

It is a cyclic number.

It is not a de Polignac number, because 140045105041 - 2⁵ = 140045105009 is a prime.

It is a super-2 number, since 2×140045105041² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140045104997 and 140045105015.

It is not a weakly prime, because it can be changed into another prime (140045103041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70022552520 + 70022552521.

It is an arithmetic number, because the mean of its divisors is an integer number (70022552521).

Almost surely, 2^140045105041 is an apocalyptic number.

It is an amenable number.

140045105041 is a deficient number, since it is larger than the sum of its proper divisors (1).

140045105041 is an equidigital number, since it uses as much as digits as its factorization.

140045105041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1600, while the sum is 25.

Adding to 140045105041 its reverse (140501540041), we get a palindrome (280546645082).

The spelling of 140045105041 in words is "one hundred forty billion, forty-five million, one hundred five thousand, forty-one".