Base | Representation |
---|---|
bin | 10100011000010001100… |
… | …000010001101111011111 |
3 | 11221212210222102012201122 |
4 | 110120101200101233133 |
5 | 140421111432344242 |
6 | 2551205332201155 |
7 | 203115350124026 |
oct | 24302140215737 |
9 | 4855728365648 |
10 | 1400453012447 |
11 | 49aa24241245 |
12 | 1a7500a691bb |
13 | a20a6719a88 |
14 | 4bad484d8bd |
15 | 26667ce5ad2 |
hex | 14611811bdf |
1400453012447 has 2 divisors, whose sum is σ = 1400453012448. Its totient is φ = 1400453012446.
The previous prime is 1400453012417. The next prime is 1400453012459. The reversal of 1400453012447 is 7442103540041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1400453012447 - 26 = 1400453012383 is a prime.
It is a super-2 number, since 2×14004530124472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400453012417) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700226506223 + 700226506224.
It is an arithmetic number, because the mean of its divisors is an integer number (700226506224).
Almost surely, 21400453012447 is an apocalyptic number.
1400453012447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400453012447 is an equidigital number, since it uses as much as digits as its factorization.
1400453012447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 53760, while the sum is 35.
Adding to 1400453012447 its reverse (7442103540041), we get a palindrome (8842556552488).
The spelling of 1400453012447 in words is "one trillion, four hundred billion, four hundred fifty-three million, twelve thousand, four hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.094 sec. • engine limits •