Search a number
-
+
140050117 is a prime number
BaseRepresentation
bin10000101100011…
…11111011000101
3100202112021122101
420112033323011
5241323100432
621521432101
73320256244
oct1026177305
9322467571
10140050117
11720667a9
123aa9b631
13230270bc
141485895b
15c4664e7
hex858fec5

140050117 has 2 divisors, whose sum is σ = 140050118. Its totient is φ = 140050116.

The previous prime is 140050111. The next prime is 140050153. The reversal of 140050117 is 711050041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 140043556 + 6561 = 11834^2 + 81^2 .

It is a cyclic number.

It is not a de Polignac number, because 140050117 - 23 = 140050109 is a prime.

It is a super-2 number, since 2×1400501172 = 39228070543427378, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140050094 and 140050103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140050111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70025058 + 70025059.

It is an arithmetic number, because the mean of its divisors is an integer number (70025059).

Almost surely, 2140050117 is an apocalyptic number.

It is an amenable number.

140050117 is a deficient number, since it is larger than the sum of its proper divisors (1).

140050117 is an equidigital number, since it uses as much as digits as its factorization.

140050117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 140, while the sum is 19.

The square root of 140050117 is about 11834.2772064879. The cubic root of 140050117 is about 519.3113628471.

The spelling of 140050117 in words is "one hundred forty million, fifty thousand, one hundred seventeen".