Base | Representation |
---|---|
bin | 101001101111010… |
… | …0000000001001001 |
3 | 10121121021222212002 |
4 | 1103132200001021 |
5 | 10332012120033 |
6 | 350545400345 |
7 | 46464043121 |
oct | 12336400111 |
9 | 3547258762 |
10 | 1400504393 |
11 | 659603752 |
12 | 3310390b5 |
13 | 1941c7232 |
14 | d4003c81 |
15 | 82e443e8 |
hex | 537a0049 |
1400504393 has 2 divisors, whose sum is σ = 1400504394. Its totient is φ = 1400504392.
The previous prime is 1400504381. The next prime is 1400504407. The reversal of 1400504393 is 3934050041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1319360329 + 81144064 = 36323^2 + 9008^2 .
It is an emirp because it is prime and its reverse (3934050041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1400504393 - 28 = 1400504137 is a prime.
It is a super-2 number, since 2×14005043932 = 3922825109624596898, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1400504093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700252196 + 700252197.
It is an arithmetic number, because the mean of its divisors is an integer number (700252197).
Almost surely, 21400504393 is an apocalyptic number.
It is an amenable number.
1400504393 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400504393 is an equidigital number, since it uses as much as digits as its factorization.
1400504393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
The square root of 1400504393 is about 37423.3134957342. The cubic root of 1400504393 is about 1118.8232733007.
The spelling of 1400504393 in words is "one billion, four hundred million, five hundred four thousand, three hundred ninety-three".
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