Search a number
-
+
14005131251 is a prime number
BaseRepresentation
bin11010000101100010…
…10101011111110011
31100011001010101022212
431002301111133303
5212140303200001
610233414322335
71004026436306
oct150261253763
940131111285
1014005131251
115a37593441
12286a3593ab
1314226b7617
1496c050b3d
1556e7e87bb
hex342c557f3

14005131251 has 2 divisors, whose sum is σ = 14005131252. Its totient is φ = 14005131250.

The previous prime is 14005131223. The next prime is 14005131253. The reversal of 14005131251 is 15213150041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14005131251 - 218 = 14004869107 is a prime.

It is a super-2 number, since 2×140051312512 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 14005131253, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14005131253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002565625 + 7002565626.

It is an arithmetic number, because the mean of its divisors is an integer number (7002565626).

Almost surely, 214005131251 is an apocalyptic number.

14005131251 is a deficient number, since it is larger than the sum of its proper divisors (1).

14005131251 is an equidigital number, since it uses as much as digits as its factorization.

14005131251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 14005131251 its reverse (15213150041), we get a palindrome (29218281292).

The spelling of 14005131251 in words is "fourteen billion, five million, one hundred thirty-one thousand, two hundred fifty-one".