Base | Representation |
---|---|
bin | 1000001001101111100… |
… | …0111000011111111101 |
3 | 111101111121221022012201 |
4 | 2002123320320133331 |
5 | 4243312402132222 |
6 | 144201242231501 |
7 | 13055451122554 |
oct | 2023370703775 |
9 | 441447838181 |
10 | 140054333437 |
11 | 54440024707 |
12 | 23187ab5591 |
13 | 1028cc06965 |
14 | 6ac8932d9b |
15 | 399a8a5427 |
hex | 209be387fd |
140054333437 has 2 divisors, whose sum is σ = 140054333438. Its totient is φ = 140054333436.
The previous prime is 140054333333. The next prime is 140054333443. The reversal of 140054333437 is 734333450041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 119656495396 + 20397838041 = 345914^2 + 142821^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140054333437 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140054333396 and 140054333405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140054336437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70027166718 + 70027166719.
It is an arithmetic number, because the mean of its divisors is an integer number (70027166719).
Almost surely, 2140054333437 is an apocalyptic number.
It is an amenable number.
140054333437 is a deficient number, since it is larger than the sum of its proper divisors (1).
140054333437 is an equidigital number, since it uses as much as digits as its factorization.
140054333437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 37.
Adding to 140054333437 its reverse (734333450041), we get a palindrome (874387783478).
The spelling of 140054333437 in words is "one hundred forty billion, fifty-four million, three hundred thirty-three thousand, four hundred thirty-seven".
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