Base | Representation |
---|---|
bin | 10100011000101100011… |
… | …000101001010000000001 |
3 | 11221220222102000120102122 |
4 | 110120230120221100001 |
5 | 140423022410341132 |
6 | 2551322202254025 |
7 | 203132464332062 |
oct | 24305430512001 |
9 | 4856872016378 |
10 | 1400903996417 |
11 | 4a013586a172 |
12 | 1a7607ab7315 |
13 | a2148c9c5b3 |
14 | 4bb386c6569 |
15 | 266926ca912 |
hex | 1462c629401 |
1400903996417 has 2 divisors, whose sum is σ = 1400903996418. Its totient is φ = 1400903996416.
The previous prime is 1400903996389. The next prime is 1400903996483. The reversal of 1400903996417 is 7146993090041.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1400236755856 + 667240561 = 1183316^2 + 25831^2 .
It is a cyclic number.
It is not a de Polignac number, because 1400903996417 - 212 = 1400903992321 is a prime.
It is not a weakly prime, because it can be changed into another prime (1400903996017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700451998208 + 700451998209.
It is an arithmetic number, because the mean of its divisors is an integer number (700451998209).
Almost surely, 21400903996417 is an apocalyptic number.
It is an amenable number.
1400903996417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400903996417 is an equidigital number, since it uses as much as digits as its factorization.
1400903996417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1469664, while the sum is 53.
The spelling of 1400903996417 in words is "one trillion, four hundred billion, nine hundred three million, nine hundred ninety-six thousand, four hundred seventeen".
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