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14010031214303 is a prime number
BaseRepresentation
bin1100101111011111011011…
…1011110000111011011111
31211121100100011102102212012
43023313312323300323133
53314020020442324203
645444041450501435
72644122430306235
oct313676673607337
954540304372765
1014010031214303
11451169141a443
1216a32a313487b
137a81a9250007
143661367d8955
151946768c4bd8
hexcbdf6ef0edf

14010031214303 has 2 divisors, whose sum is σ = 14010031214304. Its totient is φ = 14010031214302.

The previous prime is 14010031214279. The next prime is 14010031214341. The reversal of 14010031214303 is 30341213001041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14010031214303 - 212 = 14010031210207 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14010031211303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005015607151 + 7005015607152.

It is an arithmetic number, because the mean of its divisors is an integer number (7005015607152).

Almost surely, 214010031214303 is an apocalyptic number.

14010031214303 is a deficient number, since it is larger than the sum of its proper divisors (1).

14010031214303 is an equidigital number, since it uses as much as digits as its factorization.

14010031214303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 14010031214303 its reverse (30341213001041), we get a palindrome (44351244215344).

The spelling of 14010031214303 in words is "fourteen trillion, ten billion, thirty-one million, two hundred fourteen thousand, three hundred three".