Base | Representation |
---|---|
bin | 10100011000110011011… |
… | …111111000011111000111 |
3 | 11221221021201120120021211 |
4 | 110120303133320133013 |
5 | 140423243433144333 |
6 | 2551342104152251 |
7 | 203135443565053 |
oct | 24306337703707 |
9 | 4857251516254 |
10 | 1401023334343 |
11 | 4a0197169556 |
12 | 1a763ba68687 |
13 | a2167924059 |
14 | 4bb4a4acc63 |
15 | 2669cdeeecd |
hex | 146337f87c7 |
1401023334343 has 2 divisors, whose sum is σ = 1401023334344. Its totient is φ = 1401023334342.
The previous prime is 1401023334289. The next prime is 1401023334353. The reversal of 1401023334343 is 3434333201041.
It is a strong prime.
It is an emirp because it is prime and its reverse (3434333201041) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1401023334343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1401023334353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700511667171 + 700511667172.
It is an arithmetic number, because the mean of its divisors is an integer number (700511667172).
Almost surely, 21401023334343 is an apocalyptic number.
1401023334343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401023334343 is an equidigital number, since it uses as much as digits as its factorization.
1401023334343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 1401023334343 its reverse (3434333201041), we get a palindrome (4835356535384).
The spelling of 1401023334343 in words is "one trillion, four hundred one billion, twenty-three million, three hundred thirty-four thousand, three hundred forty-three".
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