Base | Representation |
---|---|
bin | 10100011000110011111… |
… | …110101010111010011101 |
3 | 11221221022021202121102221 |
4 | 110120303332222322131 |
5 | 140423303014431323 |
6 | 2551342553145341 |
7 | 203135602311226 |
oct | 24306376527235 |
9 | 4857267677387 |
10 | 1401031405213 |
11 | 4a01a07812a0 |
12 | 1a76426bb251 |
13 | a21694bb80b |
14 | 4bb4b5b024d |
15 | 2669d99655d |
hex | 14633faae9d |
1401031405213 has 16 divisors (see below), whose sum is σ = 1550401300800. Its totient is φ = 1255459254400.
The previous prime is 1401031405157. The next prime is 1401031405223. The reversal of 1401031405213 is 3125041301041.
It is a cyclic number.
It is not a de Polignac number, because 1401031405213 - 29 = 1401031404701 is a prime.
It is a super-2 number, since 2×14010314052132 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1401031405223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3047920 + ... + 3477337.
It is an arithmetic number, because the mean of its divisors is an integer number (96900081300).
Almost surely, 21401031405213 is an apocalyptic number.
It is an amenable number.
1401031405213 is a deficient number, since it is larger than the sum of its proper divisors (149369895587).
1401031405213 is a wasteful number, since it uses less digits than its factorization.
1401031405213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6525548.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1401031405213 its reverse (3125041301041), we get a palindrome (4526072706254).
The spelling of 1401031405213 in words is "one trillion, four hundred one billion, thirty-one million, four hundred five thousand, two hundred thirteen".
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