Base | Representation |
---|---|
bin | 1100101111100001010011… |
… | …0111110101100001111101 |
3 | 1211121101122011120020202011 |
4 | 3023320110313311201331 |
5 | 3314022033034013203 |
6 | 45444203352331221 |
7 | 2644141036546135 |
oct | 313702467654175 |
9 | 54541564506664 |
10 | 14010533501053 |
11 | 45119199a8961 |
12 | 16a34033a3b11 |
13 | 7a8259325bcb |
14 | 3661833c7ac5 |
15 | 1946a5a4076d |
hex | cbe14df587d |
14010533501053 has 2 divisors, whose sum is σ = 14010533501054. Its totient is φ = 14010533501052.
The previous prime is 14010533501021. The next prime is 14010533501057. The reversal of 14010533501053 is 35010533501041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13992971155524 + 17562345529 = 3740718^2 + 132523^2 .
It is a cyclic number.
It is not a de Polignac number, because 14010533501053 - 25 = 14010533501021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14010533501057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005266750526 + 7005266750527.
It is an arithmetic number, because the mean of its divisors is an integer number (7005266750527).
Almost surely, 214010533501053 is an apocalyptic number.
It is an amenable number.
14010533501053 is a deficient number, since it is larger than the sum of its proper divisors (1).
14010533501053 is an equidigital number, since it uses as much as digits as its factorization.
14010533501053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 14010533501053 in words is "fourteen trillion, ten billion, five hundred thirty-three million, five hundred one thousand, fifty-three".
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