14010544811 has 2 divisors, whose sum is σ = 14010544812. Its totient is φ = 14010544810.

The previous prime is 14010544771. The next prime is 14010544813. The reversal of 14010544811 is 11844501041.

It is a strong prime.

It is an emirp because it is prime and its reverse (11844501041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14010544811 is a prime.

Together with 14010544813, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14010544813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005272405 + 7005272406.

It is an arithmetic number, because the mean of its divisors is an integer number (7005272406).

Almost surely, 2^14010544811 is an apocalyptic number.

14010544811 is a deficient number, since it is larger than the sum of its proper divisors (1).

14010544811 is an equidigital number, since it uses as much as digits as its factorization.

14010544811 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2560, while the sum is 29.

The spelling of 14010544811 in words is "fourteen billion, ten million, five hundred forty-four thousand, eight hundred eleven".