140105553455053 has 2 divisors, whose sum is σ = 140105553455054. Its totient is φ = 140105553455052.

The previous prime is 140105553454967. The next prime is 140105553455071. The reversal of 140105553455053 is 350554355501041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 135458243654409 + 4647309800644 = 11638653^2 + 2155762^2 .

It is a cyclic number.

It is not a de Polignac number, because 140105553455053 - 2³³ = 140096963520461 is a prime.

It is a super-2 number, since 2×140105553455053² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140105553454994 and 140105553455012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140105553455353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70052776727526 + 70052776727527.

It is an arithmetic number, because the mean of its divisors is an integer number (70052776727527).

Almost surely, 2^{140105553455053} is an apocalyptic number.

It is an amenable number.

140105553455053 is a deficient number, since it is larger than the sum of its proper divisors (1).

140105553455053 is an equidigital number, since it uses as much as digits as its factorization.

140105553455053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2250000, while the sum is 46.

The spelling of 140105553455053 in words is "one hundred forty trillion, one hundred five billion, five hundred fifty-three million, four hundred fifty-five thousand, fifty-three".