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14011001302 = 27005500651
BaseRepresentation
bin11010000110001111…
…01110100111010110
31100011110011121112011
431003013232213112
5212143304020202
610234144214434
71004130355204
oct150307564726
940143147464
1014011001302
115a3a932721
12287030a41a
13142399141c
1496cb3c074
155700a7bd7
hex3431ee9d6

14011001302 has 4 divisors (see below), whose sum is σ = 21016501956. Its totient is φ = 7005500650.

The previous prime is 14011001293. The next prime is 14011001311. The reversal of 14011001302 is 20310011041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20310011041 = 88123053361.

It is an interprime number because it is at equal distance from previous prime (14011001293) and next prime (14011001311).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3502750324 + ... + 3502750327.

It is an arithmetic number, because the mean of its divisors is an integer number (5254125489).

Almost surely, 214011001302 is an apocalyptic number.

14011001302 is a deficient number, since it is larger than the sum of its proper divisors (7005500654).

14011001302 is an equidigital number, since it uses as much as digits as its factorization.

14011001302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7005500653.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 14011001302 its reverse (20310011041), we get a palindrome (34321012343).

The spelling of 14011001302 in words is "fourteen billion, eleven million, one thousand, three hundred two".

Divisors: 1 2 7005500651 14011001302