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140111211341 = 473319006313
BaseRepresentation
bin1000001001111101000…
…1110110101101001101
3111101122120222000000202
42002133101312231031
54243421432230331
6144211033303245
713060041434423
oct2023721665515
9441576860022
10140111211341
115446a142942
12231a2b64b25
131029b92c81a
146ad22db113
1539a088cecb
hex209f476b4d

140111211341 has 8 divisors (see below), whose sum is σ = 143524619904. Its totient is φ = 136715816160.

The previous prime is 140111211307. The next prime is 140111211403. The reversal of 140111211341 is 143112111041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140111211341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140111211041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4487600 + ... + 4518713.

It is an arithmetic number, because the mean of its divisors is an integer number (17940577488).

Almost surely, 2140111211341 is an apocalyptic number.

It is an amenable number.

140111211341 is a deficient number, since it is larger than the sum of its proper divisors (3413408563).

140111211341 is an equidigital number, since it uses as much as digits as its factorization.

140111211341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9006691.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 140111211341 its reverse (143112111041), we get a palindrome (283223322382).

The spelling of 140111211341 in words is "one hundred forty billion, one hundred eleven million, two hundred eleven thousand, three hundred forty-one".

Divisors: 1 47 331 15557 9006313 423296711 2981089603 140111211341