Base | Representation |
---|---|
bin | 1100101111100011100011… |
… | …1110001100100001110101 |
3 | 1211121110012101012022000121 |
4 | 3023320320332030201311 |
5 | 3314024303110213033 |
6 | 45444343425411541 |
7 | 2644162042504306 |
oct | 313707076144165 |
9 | 54543171168017 |
10 | 14011139147893 |
11 | 45120aa863338 |
12 | 16a3552199bb1 |
13 | 7a832494ab14 |
14 | 3661dda007ad |
15 | 1946ddcc662d |
hex | cbe38f8c875 |
14011139147893 has 2 divisors, whose sum is σ = 14011139147894. Its totient is φ = 14011139147892.
The previous prime is 14011139147843. The next prime is 14011139147899. The reversal of 14011139147893 is 39874193111041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13221710451889 + 789428696004 = 3636167^2 + 888498^2 .
It is a cyclic number.
It is not a de Polignac number, because 14011139147893 - 241 = 11812115892341 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14011139147893.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14011139147899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005569573946 + 7005569573947.
It is an arithmetic number, because the mean of its divisors is an integer number (7005569573947).
Almost surely, 214011139147893 is an apocalyptic number.
It is an amenable number.
14011139147893 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011139147893 is an equidigital number, since it uses as much as digits as its factorization.
14011139147893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 52.
The spelling of 14011139147893 in words is "fourteen trillion, eleven billion, one hundred thirty-nine million, one hundred forty-seven thousand, eight hundred ninety-three".
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