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14011139147893 is a prime number
BaseRepresentation
bin1100101111100011100011…
…1110001100100001110101
31211121110012101012022000121
43023320320332030201311
53314024303110213033
645444343425411541
72644162042504306
oct313707076144165
954543171168017
1014011139147893
1145120aa863338
1216a3552199bb1
137a832494ab14
143661dda007ad
151946ddcc662d
hexcbe38f8c875

14011139147893 has 2 divisors, whose sum is σ = 14011139147894. Its totient is φ = 14011139147892.

The previous prime is 14011139147843. The next prime is 14011139147899. The reversal of 14011139147893 is 39874193111041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13221710451889 + 789428696004 = 3636167^2 + 888498^2 .

It is a cyclic number.

It is not a de Polignac number, because 14011139147893 - 241 = 11812115892341 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14011139147893.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14011139147899) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005569573946 + 7005569573947.

It is an arithmetic number, because the mean of its divisors is an integer number (7005569573947).

Almost surely, 214011139147893 is an apocalyptic number.

It is an amenable number.

14011139147893 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011139147893 is an equidigital number, since it uses as much as digits as its factorization.

14011139147893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 653184, while the sum is 52.

The spelling of 14011139147893 in words is "fourteen trillion, eleven billion, one hundred thirty-nine million, one hundred forty-seven thousand, eight hundred ninety-three".