Base | Representation |
---|---|
bin | 1100101111100011111001… |
… | …1000111000111001101111 |
3 | 1211121110102201012122212001 |
4 | 3023320332120320321233 |
5 | 3314024444342001341 |
6 | 45444400433353131 |
7 | 2644164225140101 |
oct | 313707630707157 |
9 | 54543381178761 |
10 | 14011230031471 |
11 | 4512147098532 |
12 | 16a35787087a7 |
13 | 7a833a71bc9a |
14 | 36620badb571 |
15 | 1946e6c79d31 |
hex | cbe3e638e6f |
14011230031471 has 2 divisors, whose sum is σ = 14011230031472. Its totient is φ = 14011230031470.
The previous prime is 14011230031439. The next prime is 14011230031483. The reversal of 14011230031471 is 17413003211041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14011230031471 - 25 = 14011230031439 is a prime.
It is a super-3 number, since 3×140112300314713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14011230031171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005615015735 + 7005615015736.
It is an arithmetic number, because the mean of its divisors is an integer number (7005615015736).
Almost surely, 214011230031471 is an apocalyptic number.
14011230031471 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011230031471 is an equidigital number, since it uses as much as digits as its factorization.
14011230031471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 28.
The spelling of 14011230031471 in words is "fourteen trillion, eleven billion, two hundred thirty million, thirty-one thousand, four hundred seventy-one".
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