Base | Representation |
---|---|
bin | 10100011000111001011… |
… | …100100010001111111010 |
3 | 11221221112200100012122102 |
4 | 110120321130202033322 |
5 | 140424000004320442 |
6 | 2551400031023402 |
7 | 203141065005515 |
oct | 24307134421772 |
9 | 4857480305572 |
10 | 1401123120122 |
11 | 4a0238524040 |
12 | 1a766936ab62 |
13 | a21824c11ab |
14 | 4bb59845d7c |
15 | 266a6a61232 |
hex | 146397223fa |
1401123120122 has 32 divisors (see below), whose sum is σ = 2440324537344. Its totient is φ = 596272652800.
The previous prime is 1401123120113. The next prime is 1401123120157. The reversal of 1401123120122 is 2210213211041.
It is a junction number, because it is equal to n+sod(n) for n = 1401123120094 and 1401123120103.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9735683 + ... + 9878550.
It is an arithmetic number, because the mean of its divisors is an integer number (76260141792).
Almost surely, 21401123120122 is an apocalyptic number.
1401123120122 is a deficient number, since it is larger than the sum of its proper divisors (1039201417222).
1401123120122 is a wasteful number, since it uses less digits than its factorization.
1401123120122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19614454.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1401123120122 its reverse (2210213211041), we get a palindrome (3611336331163).
The spelling of 1401123120122 in words is "one trillion, four hundred one billion, one hundred twenty-three million, one hundred twenty thousand, one hundred twenty-two".
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