Base | Representation |
---|---|
bin | 1100101111100011111100… |
… | …1100000101100000011011 |
3 | 1211121110110122110111222002 |
4 | 3023320333030011200123 |
5 | 3314030011310434233 |
6 | 45444402033151215 |
7 | 2644164450205226 |
oct | 313707714054033 |
9 | 54543418414862 |
10 | 14011243452443 |
11 | 4512153724946 |
12 | 16a35810bb50b |
13 | 7a834043a9a3 |
14 | 36620d7d25bd |
15 | 1946e802b6e8 |
hex | cbe3f30581b |
14011243452443 has 2 divisors, whose sum is σ = 14011243452444. Its totient is φ = 14011243452442.
The previous prime is 14011243452407. The next prime is 14011243452469. The reversal of 14011243452443 is 34425434211041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14011243452443 - 224 = 14011226675227 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14011243452397 and 14011243452406.
It is not a weakly prime, because it can be changed into another prime (14011246452443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005621726221 + 7005621726222.
It is an arithmetic number, because the mean of its divisors is an integer number (7005621726222).
Almost surely, 214011243452443 is an apocalyptic number.
14011243452443 is a deficient number, since it is larger than the sum of its proper divisors (1).
14011243452443 is an equidigital number, since it uses as much as digits as its factorization.
14011243452443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 184320, while the sum is 38.
Adding to 14011243452443 its reverse (34425434211041), we get a palindrome (48436677663484).
The spelling of 14011243452443 in words is "fourteen trillion, eleven billion, two hundred forty-three million, four hundred fifty-two thousand, four hundred forty-three".
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