Base | Representation |
---|---|
bin | 1100101111100100001101… |
… | …1001100101110010100100 |
3 | 1211121110122120101212010120 |
4 | 3023321003121211302210 |
5 | 3314030132402221122 |
6 | 45444413035321540 |
7 | 2644166265544005 |
oct | 313710331456244 |
9 | 54543576355116 |
10 | 14011314101412 |
11 | 451218a599521 |
12 | 16a35a08b02b0 |
13 | 7a8351c75a04 |
14 | 366218d431ac |
15 | 1946ee33475c |
hex | cbe43665ca4 |
14011314101412 has 48 divisors (see below), whose sum is σ = 33211499798400. Its totient is φ = 4596943622400.
The previous prime is 14011314101401. The next prime is 14011314101423. The reversal of 14011314101412 is 21410141311041.
It is a happy number.
14011314101412 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (14011314101401) and next prime (14011314101423).
It is a super-2 number, since 2×140113141014122 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35272737 + ... + 35667752.
It is an arithmetic number, because the mean of its divisors is an integer number (691906245800).
Almost surely, 214011314101412 is an apocalyptic number.
14011314101412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14011314101412 is an abundant number, since it is smaller than the sum of its proper divisors (19200185696988).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14011314101412 is a wasteful number, since it uses less digits than its factorization.
14011314101412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70940756 (or 70940754 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 24.
Adding to 14011314101412 its reverse (21410141311041), we get a palindrome (35421455412453).
The spelling of 14011314101412 in words is "fourteen trillion, eleven billion, three hundred fourteen million, one hundred one thousand, four hundred twelve".
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