Base | Representation |
---|---|
bin | 1100101111100100001111… |
… | …1100000101000010111010 |
3 | 1211121110200012102011221101 |
4 | 3023321003330011002322 |
5 | 3314030142211023310 |
6 | 45444414001202014 |
7 | 2644166435440243 |
oct | 313710374050272 |
9 | 54543605364841 |
10 | 14011323142330 |
11 | 4512194704058 |
12 | 16a35a393030a |
13 | 7a8353abcb77 |
14 | 36621a217cca |
15 | 19470001d43a |
hex | cbe43f050ba |
14011323142330 has 32 divisors (see below), whose sum is σ = 26356854902400. Its totient is φ = 5352719182272.
The previous prime is 14011323142321. The next prime is 14011323142367. The reversal of 14011323142330 is 3324132311041.
14011323142330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×140113231423303 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46069065 + ... + 46372204.
It is an arithmetic number, because the mean of its divisors is an integer number (823651715700).
Almost surely, 214011323142330 is an apocalyptic number.
14011323142330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14011323142330 is a deficient number, since it is larger than the sum of its proper divisors (12345531760070).
14011323142330 is a wasteful number, since it uses less digits than its factorization.
14011323142330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92441958.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 14011323142330 its reverse (3324132311041), we get a palindrome (17335455453371).
The spelling of 14011323142330 in words is "fourteen trillion, eleven billion, three hundred twenty-three million, one hundred forty-two thousand, three hundred thirty".
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