Base | Representation |
---|---|
bin | 11111110110111010110001… |
… | …011101001000001100111001 |
3 | 200101002201011202222100002201 |
4 | 133312322301131020030321 |
5 | 121331104220441124423 |
6 | 1213555112453430201 |
7 | 41340600451152124 |
oct | 3766726135101471 |
9 | 611081152870081 |
10 | 140113400333113 |
11 | 4070a839814a09 |
12 | 1386aaba33b361 |
13 | 602483851bc1c |
14 | 268574bd273bb |
15 | 112ea0eda52ad |
hex | 7f6eb1748339 |
140113400333113 has 2 divisors, whose sum is σ = 140113400333114. Its totient is φ = 140113400333112.
The previous prime is 140113400333059. The next prime is 140113400333183. The reversal of 140113400333113 is 311333004311041.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 133266637309689 + 6846763023424 = 11544117^2 + 2616632^2 .
It is a cyclic number.
It is not a de Polignac number, because 140113400333113 - 221 = 140113398235961 is a prime.
It is not a weakly prime, because it can be changed into another prime (140113400333183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70056700166556 + 70056700166557.
It is an arithmetic number, because the mean of its divisors is an integer number (70056700166557).
Almost surely, 2140113400333113 is an apocalyptic number.
It is an amenable number.
140113400333113 is a deficient number, since it is larger than the sum of its proper divisors (1).
140113400333113 is an equidigital number, since it uses as much as digits as its factorization.
140113400333113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 140113400333113 its reverse (311333004311041), we get a palindrome (451446404644154).
The spelling of 140113400333113 in words is "one hundred forty trillion, one hundred thirteen billion, four hundred million, three hundred thirty-three thousand, one hundred thirteen".
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