140113400381 has 2 divisors, whose sum is σ = 140113400382. Its totient is φ = 140113400380.

The previous prime is 140113400363. The next prime is 140113400389. The reversal of 140113400381 is 183004311041.

140113400381 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87255252100 + 52858148281 = 295390^2 + 229909^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140113400381 is a prime.

It is a super-2 number, since 2×140113400381² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 140113400381.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140113400389) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70056700190 + 70056700191.

It is an arithmetic number, because the mean of its divisors is an integer number (70056700191).

Almost surely, 2^140113400381 is an apocalyptic number.

It is an amenable number.

140113400381 is a deficient number, since it is larger than the sum of its proper divisors (1).

140113400381 is an equidigital number, since it uses as much as digits as its factorization.

140113400381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 26.

The spelling of 140113400381 in words is "one hundred forty billion, one hundred thirteen million, four hundred thousand, three hundred eighty-one".