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14011342310401 is a prime number
BaseRepresentation
bin1100101111100100010100…
…0101001100110000000001
31211121110201112111000120221
43023321011011030300001
53314030212112413101
645444415524103041
72644200060402652
oct313710505146001
954543645430527
1014011342310401
1145121a4506337
1216a35aa234a81
137a8357a71717
1436621c9a7529
15194701a57aa1
hexcbe4514cc01

14011342310401 has 2 divisors, whose sum is σ = 14011342310402. Its totient is φ = 14011342310400.

The previous prime is 14011342310393. The next prime is 14011342310423. The reversal of 14011342310401 is 10401324311041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13582350059776 + 428992250625 = 3685424^2 + 654975^2 .

It is an emirp because it is prime and its reverse (10401324311041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14011342310401 - 23 = 14011342310393 is a prime.

It is not a weakly prime, because it can be changed into another prime (14011342310501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005671155200 + 7005671155201.

It is an arithmetic number, because the mean of its divisors is an integer number (7005671155201).

Almost surely, 214011342310401 is an apocalyptic number.

It is an amenable number.

14011342310401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011342310401 is an equidigital number, since it uses as much as digits as its factorization.

14011342310401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14011342310401 its reverse (10401324311041), we get a palindrome (24412666621442).

The spelling of 14011342310401 in words is "fourteen trillion, eleven billion, three hundred forty-two million, three hundred ten thousand, four hundred one".