Base | Representation |
---|---|
bin | 10100011000111010100… |
… | …001101000000111111011 |
3 | 11221221120221102101122021 |
4 | 110120322201220013323 |
5 | 140424014123411443 |
6 | 2551401515135311 |
7 | 203141404652263 |
oct | 24307241500773 |
9 | 4857527371567 |
10 | 1401141232123 |
11 | 4a0247774936 |
12 | 1a7673444537 |
13 | a2186193159 |
14 | 4bb5bddc7a3 |
15 | 266a843c9ed |
hex | 1463a8681fb |
1401141232123 has 2 divisors, whose sum is σ = 1401141232124. Its totient is φ = 1401141232122.
The previous prime is 1401141232037. The next prime is 1401141232151. The reversal of 1401141232123 is 3212321411041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1401141232123 - 213 = 1401141223931 is a prime.
It is not a weakly prime, because it can be changed into another prime (1401141232193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700570616061 + 700570616062.
It is an arithmetic number, because the mean of its divisors is an integer number (700570616062).
Almost surely, 21401141232123 is an apocalyptic number.
1401141232123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401141232123 is an equidigital number, since it uses as much as digits as its factorization.
1401141232123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1401141232123 its reverse (3212321411041), we get a palindrome (4613462643164).
The spelling of 1401141232123 in words is "one trillion, four hundred one billion, one hundred forty-one million, two hundred thirty-two thousand, one hundred twenty-three".
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