1401171142333 has 2 divisors, whose sum is σ = 1401171142334. Its totient is φ = 1401171142332.

The previous prime is 1401171142313. The next prime is 1401171142361. The reversal of 1401171142333 is 3332411711041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1400807172249 + 363970084 = 1183557^2 + 19078^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401171142333 - 2²¹ = 1401169045181 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1401171142295 and 1401171142304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1401171142313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700585571166 + 700585571167.

It is an arithmetic number, because the mean of its divisors is an integer number (700585571167).

Almost surely, 2^{1401171142333} is an apocalyptic number.

It is an amenable number.

1401171142333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401171142333 is an equidigital number, since it uses as much as digits as its factorization.

1401171142333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 1401171142333 its reverse (3332411711041), we get a palindrome (4733582853374).

The spelling of 1401171142333 in words is "one trillion, four hundred one billion, one hundred seventy-one million, one hundred forty-two thousand, three hundred thirty-three".