14012031413041 has 2 divisors, whose sum is σ = 14012031413042. Its totient is φ = 14012031413040.

The previous prime is 14012031412999. The next prime is 14012031413059. The reversal of 14012031413041 is 14031413021041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13502979129600 + 509052283441 = 3674640^2 + 713479^2 .

It is a cyclic number.

It is not a de Polignac number, because 14012031413041 - 2¹⁵ = 14012031380273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14012031412997 and 14012031413015.

It is not a weakly prime, because it can be changed into another prime (14012031413141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006015706520 + 7006015706521.

It is an arithmetic number, because the mean of its divisors is an integer number (7006015706521).

Almost surely, 2^{14012031413041} is an apocalyptic number.

It is an amenable number.

14012031413041 is a deficient number, since it is larger than the sum of its proper divisors (1).

14012031413041 is an equidigital number, since it uses as much as digits as its factorization.

14012031413041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14012031413041 its reverse (14031413021041), we get a palindrome (28043444434082).

The spelling of 14012031413041 in words is "fourteen trillion, twelve billion, thirty-one million, four hundred thirteen thousand, forty-one".