14012043444111 has 4 divisors (see below), whose sum is σ = 18682724592152. Its totient is φ = 9341362296072.

The previous prime is 14012043444089. The next prime is 14012043444121. The reversal of 14012043444111 is 11144434021041.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14012043444111 - 2¹⁷ = 14012043313039 is a prime.

It is a super-2 number, since 2×14012043444111² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14012043444121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335340574016 + ... + 2335340574021.

It is an arithmetic number, because the mean of its divisors is an integer number (4670681148038).

Almost surely, 2^{14012043444111} is an apocalyptic number.

14012043444111 is a deficient number, since it is larger than the sum of its proper divisors (4670681148041).

14012043444111 is an equidigital number, since it uses as much as digits as its factorization.

14012043444111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4670681148040.

The product of its (nonzero) digits is 6144, while the sum is 30.

Adding to 14012043444111 its reverse (11144434021041), we get a palindrome (25156477465152).

The spelling of 14012043444111 in words is "fourteen trillion, twelve billion, forty-three million, four hundred forty-four thousand, one hundred eleven".