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140121531990311 is a prime number
BaseRepresentation
bin11111110111000010010110…
…001000111100000100100111
3200101010111011111010022201112
4133313002112020330010213
5121331222344142142221
61214002535415215235
741341306121124404
oct3767022610740447
9611114144108645
10140121531990311
1140713231936363
12138705a967751b
13602553310abc1
142685cbdca32ab
15112ed38c0a15b
hex7f709623c127

140121531990311 has 2 divisors, whose sum is σ = 140121531990312. Its totient is φ = 140121531990310.

The previous prime is 140121531990289. The next prime is 140121531990347. The reversal of 140121531990311 is 113099135121041.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140121531990311 is a prime.

It is a super-3 number, since 3×1401215319903113 (a number of 43 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140121531990371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060765995155 + 70060765995156.

It is an arithmetic number, because the mean of its divisors is an integer number (70060765995156).

Almost surely, 2140121531990311 is an apocalyptic number.

140121531990311 is a deficient number, since it is larger than the sum of its proper divisors (1).

140121531990311 is an equidigital number, since it uses as much as digits as its factorization.

140121531990311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 29160, while the sum is 41.

The spelling of 140121531990311 in words is "one hundred forty trillion, one hundred twenty-one billion, five hundred thirty-one million, nine hundred ninety thousand, three hundred eleven".