Base | Representation |
---|---|
bin | 11111110111000010010110… |
… | …001001111011111101100111 |
3 | 200101010111011111121121200222 |
4 | 133313002112021323331213 |
5 | 121331222344224031012 |
6 | 1214002535424554555 |
7 | 41341306123264355 |
oct | 3767022611737547 |
9 | 611114144547628 |
10 | 140121532252007 |
11 | 40713231aa4a39 |
12 | 138705a9782a5b |
13 | 60255331a0057 |
14 | 2685cbdd307d5 |
15 | 112ed38c5c972 |
hex | 7f709627bf67 |
140121532252007 has 2 divisors, whose sum is σ = 140121532252008. Its totient is φ = 140121532252006.
The previous prime is 140121532252001. The next prime is 140121532252081. The reversal of 140121532252007 is 700252235121041.
It is a weak prime.
It is an emirp because it is prime and its reverse (700252235121041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 140121532252007 - 28 = 140121532251751 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140121532252001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70060766126003 + 70060766126004.
It is an arithmetic number, because the mean of its divisors is an integer number (70060766126004).
Almost surely, 2140121532252007 is an apocalyptic number.
140121532252007 is a deficient number, since it is larger than the sum of its proper divisors (1).
140121532252007 is an equidigital number, since it uses as much as digits as its factorization.
140121532252007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33600, while the sum is 35.
Adding to 140121532252007 its reverse (700252235121041), we get a palindrome (840373767373048).
The spelling of 140121532252007 in words is "one hundred forty trillion, one hundred twenty-one billion, five hundred thirty-two million, two hundred fifty-two thousand, seven".
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