Base | Representation |
---|---|
bin | 11111110111000010111001… |
… | …011000111110011100010011 |
3 | 200101010112200200221220000122 |
4 | 133313002321120332130103 |
5 | 121331230102042200013 |
6 | 1214003114223140455 |
7 | 41341326562032665 |
oct | 3767027130763423 |
9 | 611115620856018 |
10 | 140122123396883 |
11 | 40713505754921 |
12 | 1387073374472b |
13 | 60255c87b8214 |
14 | 2685d38650535 |
15 | 112ed70acba08 |
hex | 7f70b963e713 |
140122123396883 has 2 divisors, whose sum is σ = 140122123396884. Its totient is φ = 140122123396882.
The previous prime is 140122123396861. The next prime is 140122123396901. The reversal of 140122123396883 is 388693321221041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140122123396883 - 216 = 140122123331347 is a prime.
It is not a weakly prime, because it can be changed into another prime (140122123396483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061061698441 + 70061061698442.
It is an arithmetic number, because the mean of its divisors is an integer number (70061061698442).
Almost surely, 2140122123396883 is an apocalyptic number.
140122123396883 is a deficient number, since it is larger than the sum of its proper divisors (1).
140122123396883 is an equidigital number, since it uses as much as digits as its factorization.
140122123396883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2985984, while the sum is 53.
The spelling of 140122123396883 in words is "one hundred forty trillion, one hundred twenty-two billion, one hundred twenty-three million, three hundred ninety-six thousand, eight hundred eighty-three".
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