Base | Representation |
---|---|
bin | 1000001001111111111… |
… | …1110010111001001111 |
3 | 111101200102121211221011 |
4 | 2002133333302321033 |
5 | 4243433023114401 |
6 | 144212143350051 |
7 | 13060246003303 |
oct | 2023777627117 |
9 | 441612554834 |
10 | 140123254351 |
11 | 54475a18a43 |
12 | 231a6bb2327 |
13 | 102a1288272 |
14 | 6ad3b53d03 |
15 | 39a196b451 |
hex | 209fff2e4f |
140123254351 has 2 divisors, whose sum is σ = 140123254352. Its totient is φ = 140123254350.
The previous prime is 140123254291. The next prime is 140123254387. The reversal of 140123254351 is 153452321041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140123254351 - 227 = 139989036623 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140123254651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70061627175 + 70061627176.
It is an arithmetic number, because the mean of its divisors is an integer number (70061627176).
Almost surely, 2140123254351 is an apocalyptic number.
140123254351 is a deficient number, since it is larger than the sum of its proper divisors (1).
140123254351 is an equidigital number, since it uses as much as digits as its factorization.
140123254351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 140123254351 its reverse (153452321041), we get a palindrome (293575575392).
The spelling of 140123254351 in words is "one hundred forty billion, one hundred twenty-three million, two hundred fifty-four thousand, three hundred fifty-one".
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