Search a number
-
+
140124722623253 is a prime number
BaseRepresentation
bin11111110111000101010100…
…010100001111001100010101
3200101010210101211212021021222
4133313011110110033030111
5121331300412442421003
61214004224153420125
741341451153062304
oct3767052424171425
9611123354767258
10140124722623253
1140714619971095
121387113a10a645
136025921149ca4
14268610393043b
15112ee73da7c38
hex7f715450f315

140124722623253 has 2 divisors, whose sum is σ = 140124722623254. Its totient is φ = 140124722623252.

The previous prime is 140124722623013. The next prime is 140124722623307. The reversal of 140124722623253 is 352326227421041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138785198788369 + 1339523834884 = 11780713^2 + 1157378^2 .

It is a cyclic number.

It is not a de Polignac number, because 140124722623253 - 216 = 140124722557717 is a prime.

It is a super-2 number, since 2×1401247226232532 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140124722623553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70062361311626 + 70062361311627.

It is an arithmetic number, because the mean of its divisors is an integer number (70062361311627).

Almost surely, 2140124722623253 is an apocalyptic number.

It is an amenable number.

140124722623253 is a deficient number, since it is larger than the sum of its proper divisors (1).

140124722623253 is an equidigital number, since it uses as much as digits as its factorization.

140124722623253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 967680, while the sum is 44.

The spelling of 140124722623253 in words is "one hundred forty trillion, one hundred twenty-four billion, seven hundred twenty-two million, six hundred twenty-three thousand, two hundred fifty-three".