Base | Representation |
---|---|
bin | 1000001010000001100… |
… | …1111111101001011101 |
3 | 111101200220112210000212 |
4 | 2002200121333221131 |
5 | 4243441302403313 |
6 | 144212550502205 |
7 | 13060361246465 |
oct | 2024031775135 |
9 | 441626483025 |
10 | 140130122333 |
11 | 54479889a63 |
12 | 231a9364965 |
13 | 102a2821366 |
14 | 6ad4a20ba5 |
15 | 39a23763a8 |
hex | 20a067fa5d |
140130122333 has 2 divisors, whose sum is σ = 140130122334. Its totient is φ = 140130122332.
The previous prime is 140130122329. The next prime is 140130122359. The reversal of 140130122333 is 333221031041.
140130122333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 110371457284 + 29758665049 = 332222^2 + 172507^2 .
It is an emirp because it is prime and its reverse (333221031041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 140130122333 - 22 = 140130122329 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140130122299 and 140130122308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140130122233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70065061166 + 70065061167.
It is an arithmetic number, because the mean of its divisors is an integer number (70065061167).
Almost surely, 2140130122333 is an apocalyptic number.
It is an amenable number.
140130122333 is a deficient number, since it is larger than the sum of its proper divisors (1).
140130122333 is an equidigital number, since it uses as much as digits as its factorization.
140130122333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 140130122333 its reverse (333221031041), we get a palindrome (473351153374).
The spelling of 140130122333 in words is "one hundred forty billion, one hundred thirty million, one hundred twenty-two thousand, three hundred thirty-three".
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