Base | Representation |
---|---|
bin | 11111110111001010100010… |
… | …100010101100000000111111 |
3 | 200101011022212122010121010201 |
4 | 133313022202202230000333 |
5 | 121331343403440021341 |
6 | 1214010552423144331 |
7 | 41342040132025615 |
oct | 3767124242540077 |
9 | 611138778117121 |
10 | 140130330001471 |
11 | 40716a37106367 |
12 | 13872243ba50a7 |
13 | 6026305a88874 |
14 | 26864b65396b5 |
15 | 11301a12d8331 |
hex | 7f72a28ac03f |
140130330001471 has 2 divisors, whose sum is σ = 140130330001472. Its totient is φ = 140130330001470.
The previous prime is 140130330001411. The next prime is 140130330001537. The reversal of 140130330001471 is 174100033031041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140130330001471 - 215 = 140130329968703 is a prime.
It is a super-3 number, since 3×1401303300014713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140130330001411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70065165000735 + 70065165000736.
It is an arithmetic number, because the mean of its divisors is an integer number (70065165000736).
Almost surely, 2140130330001471 is an apocalyptic number.
140130330001471 is a deficient number, since it is larger than the sum of its proper divisors (1).
140130330001471 is an equidigital number, since it uses as much as digits as its factorization.
140130330001471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 28.
The spelling of 140130330001471 in words is "one hundred forty trillion, one hundred thirty billion, three hundred thirty million, one thousand, four hundred seventy-one".
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