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140130959993 is a prime number
BaseRepresentation
bin1000001010000001110…
…1001100001001111001
3111101200222010100002022
42002200131030021321
54243442011204433
6144213020444225
713060401335603
oct2024035141171
9441628110068
10140130959993
115447a301342
12231a96a9675
13102a2a5570b
146ad4b9c173
1539a248e698
hex20a074c279

140130959993 has 2 divisors, whose sum is σ = 140130959994. Its totient is φ = 140130959992.

The previous prime is 140130959987. The next prime is 140130960007. The reversal of 140130959993 is 399959031041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139795227664 + 335732329 = 373892^2 + 18323^2 .

It is an emirp because it is prime and its reverse (399959031041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140130959993 - 210 = 140130958969 is a prime.

It is not a weakly prime, because it can be changed into another prime (140130959963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70065479996 + 70065479997.

It is an arithmetic number, because the mean of its divisors is an integer number (70065479997).

Almost surely, 2140130959993 is an apocalyptic number.

It is an amenable number.

140130959993 is a deficient number, since it is larger than the sum of its proper divisors (1).

140130959993 is an equidigital number, since it uses as much as digits as its factorization.

140130959993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1180980, while the sum is 53.

The spelling of 140130959993 in words is "one hundred forty billion, one hundred thirty million, nine hundred fifty-nine thousand, nine hundred ninety-three".